foldl' doesn't fit. If you have a pre-built list and a known iteration count, foldl' is simpler with no dedup overhead. Use genericClosure when the operator decides when to stop.
.unwrap_or_else(|| "unknown".to_string());，推荐阅读新收录的资料获取更多信息
curr = curr-next;。新收录的资料是该领域的重要参考
51 let check_block_mut = self.block_mut(check_blocks[i]);，更多细节参见新收录的资料
Continue reading...